Check the Leap Year in Python

In this Python lesson, we will practice how to write a program that will check if a year is a leap year or not. A year is a leap year if the year is a multiple of 400 or the year is a multiple of 4 and not a multiple of 100.

Example: Check Leap Year Using Nested if…else

# request year input from user
year = int(input('Enter a year: '))

if (year % 4) == 0:
   if (year % 100) == 0:
       if (year % 400) == 0:
           print('{0} is a leap year'.format(year))
       else:
           print('{0} is not a leap year'.format(year))
   else:
       print('{0} is a leap year'.format(year))
else:
   print('{0} is not a leap year'.format(year))

Output

Enter a year: 2032
2032 is a leap year

Here, we created a program that checks if a year is a leap year or not using the nested if-else statement. You can test for other years to know which year is a leap or not.

Do you want to become an expert programmer? See books helping our students, interns, and beginners in software companies today (Click here)!